2х + 2у = 4
1) (0;2)
2×0 + 2×2 = 4
4 = 4
2) (2;0)
2 × 2 + 2 × 0 = 4
3) (1;1)
2×1 + 2×1 = 4
2 + 2 = 4
4) (0;0)
2×0 + 2×0 ≠ 4
0 ≠ 4
Ответ: 1,2,3
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2х + 2у = 4
1) (0;2)
2×0 + 2×2 = 4
4 = 4
2) (2;0)
2 × 2 + 2 × 0 = 4
4 = 4
3) (1;1)
2×1 + 2×1 = 4
2 + 2 = 4
4 = 4
4) (0;0)
2×0 + 2×0 ≠ 4
0 ≠ 4
Ответ: 1,2,3