Ответ:
AE = FD = 3
DC=EF = 4
AD = AE+EF+FD = 3 + 3 +4 = 10 см
BE=BC = 4см
по теореме Пифагора
[tex]AB^2 = AE^2+BE^2\\AB^2 = 9+16 = 25\\AB = 5[/tex]
AB = CD
P = AB+BC+CD+AD = 5 + 4 + 5 +10 = 24 см
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Ответ:
AE = FD = 3
DC=EF = 4
AD = AE+EF+FD = 3 + 3 +4 = 10 см
BE=BC = 4см
по теореме Пифагора
[tex]AB^2 = AE^2+BE^2\\AB^2 = 9+16 = 25\\AB = 5[/tex]
AB = CD
P = AB+BC+CD+AD = 5 + 4 + 5 +10 = 24 см