Ответ:
1) M(Al2O3)=27*2+16*3=102 г/моль
w(Al)=27*2/102*100%=53%
2) M(FeCl2=56+35,5*2=127 г/моль
w(Fe)=56/127*100%=44%
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Ответ:
1) M(Al2O3)=27*2+16*3=102 г/моль
w(Al)=27*2/102*100%=53%
2) M(FeCl2=56+35,5*2=127 г/моль
w(Fe)=56/127*100%=44%