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davidvica
@davidvica
August 2022
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Алгебра 1 уравнение
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AnonimusPro
Verified answer
5(1-sin^2x)-9sinx=9
sinx=u;
5-5u^2-9u-9=0
5u^2+9u+4=0;
D=1; u1=-9+1/10=-4/5; u2=-1
sinx=-1; x=-pi/2+2pi*n
sinx=-4/5; x=arcsin(-4/5)
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Answers & Comments
Verified answer
5(1-sin^2x)-9sinx=9sinx=u;
5-5u^2-9u-9=0
5u^2+9u+4=0;
D=1; u1=-9+1/10=-4/5; u2=-1
sinx=-1; x=-pi/2+2pi*n
sinx=-4/5; x=arcsin(-4/5)