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helpMePlease11111
@helpMePlease11111
September 2021
1
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Алгебра 10 класс
срочно!
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oganesbagoyan
Verified answer
1)
(x+1)(x+7)(x-3)²/(x-1)(x+1) ≤0 ; * * * x ≠ ±1 * * *
x =3
решение.
(x+7)/(x-1)≤0⇒ x∈[ -7 ; 1) из интервала исключаем x= -1.
ответ: x∈
[ -7;-1)U(-1;1) U {3}
.
2)
(x-5)(4-x)(x-3)² (x+6)^(15) ≥0
(x+6)^(15)*(x-3)²(x-4)(x-5) ≤0 ;
- + + - +
--------- [-6] --------[3] ---------[4]--------[5]-----------
ответ: x∈
( -
∞
;-6] U
{3}
U
[4;5] .
3)
(x²-11x+30)/(x-2)(x-3) <0;
(x-5)(x-6)/(x-2)(x-3) <0;
⇔(x-2)(x-3)(x-5)(x-6) <0 ;
+ - + - +
--------- 2 -------- 3 ---------5--------6---------
ответ: x∈
( 2
;3] U
( 5 ;6).
4) x
² +11x+30 ≥ 0 ;
(x+6)(x+5) ≥ 0 ;
+ - +
--------- [ -6] -------- [-5] --------
ответ: x∈
( -
∞
; -6] U
[ -5 ;
∞
).
1 votes
Thanks 1
helpMePlease11111
Спасибо!
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Answers & Comments
Verified answer
1) (x+1)(x+7)(x-3)²/(x-1)(x+1) ≤0 ; * * * x ≠ ±1 * * *x =3 решение.
(x+7)/(x-1)≤0⇒ x∈[ -7 ; 1) из интервала исключаем x= -1.
ответ: x∈ [ -7;-1)U(-1;1) U {3} .
2) (x-5)(4-x)(x-3)² (x+6)^(15) ≥0
(x+6)^(15)*(x-3)²(x-4)(x-5) ≤0 ;
- + + - +
--------- [-6] --------[3] ---------[4]--------[5]-----------
ответ: x∈ ( -∞;-6] U {3} U [4;5] .
3) (x²-11x+30)/(x-2)(x-3) <0;
(x-5)(x-6)/(x-2)(x-3) <0;
⇔(x-2)(x-3)(x-5)(x-6) <0 ;
+ - + - +
--------- 2 -------- 3 ---------5--------6---------
ответ: x∈ ( 2;3] U ( 5 ;6).
4) x² +11x+30 ≥ 0 ;
(x+6)(x+5) ≥ 0 ;
+ - +
--------- [ -6] -------- [-5] --------
ответ: x∈ ( -∞; -6] U [ -5 ;∞).