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marner93
@marner93
August 2022
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Алгебра 10ый класс - 25 баллов
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Answers & Comments
3.
4.![\frac{\sqrt[3]{x} +\sqrt[3]{y}}{\sqrt[3]{x^{2}} -\sqrt[3]{y^{2}}} =\frac{\sqrt[3]{x}+\sqrt[3]{y}}{(\sqrt[3]{x}-\sqrt[3]{y}) *(\sqrt[3]{x}+\sqrt[3]{y})} =\frac{1}{\sqrt[3]{x}-\sqrt[3]{y}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%7D%20%2B%5Csqrt%5B3%5D%7By%7D%7D%7B%5Csqrt%5B3%5D%7Bx%5E%7B2%7D%7D%20-%5Csqrt%5B3%5D%7By%5E%7B2%7D%7D%7D%20%3D%5Cfrac%7B%5Csqrt%5B3%5D%7Bx%7D%2B%5Csqrt%5B3%5D%7By%7D%7D%7B%28%5Csqrt%5B3%5D%7Bx%7D-%5Csqrt%5B3%5D%7By%7D%29%20%2A%28%5Csqrt%5B3%5D%7Bx%7D%2B%5Csqrt%5B3%5D%7By%7D%29%7D%20%3D%5Cfrac%7B1%7D%7B%5Csqrt%5B3%5D%7Bx%7D-%5Csqrt%5B3%5D%7By%7D%7D "\frac{\sqrt[3]{x} +\sqrt[3]{y}}{\sqrt[3]{x^{2}} -\sqrt[3]{y^{2}}} =\frac{\sqrt[3]{x}+\sqrt[3]{y}}{(\sqrt[3]{x}-\sqrt[3]{y}) *(\sqrt[3]{x}+\sqrt[3]{y})} =\frac{1}{\sqrt[3]{x}-\sqrt[3]{y}}")