Ответ:
1) 2.5
2) 0,0078
3) x ∈ (4; 10]
Зная x, подставим
2)
3)
[tex]\left \{ {{12 - 6x \geq 2- 5x} \atop {4x+12 < 5x + 8 }} \right.\\
[tex]\left \{ {{10 \geq x} \atop {4 < x }} \right.\\
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Answers & Comments
Ответ:
1) 2.5
2) 0,0078
3) x ∈ (4; 10]
Зная x, подставим
2)
3)
[tex]\left \{ {{12 - 6x \geq 2- 5x} \atop {4x+12 < 5x + 8 }} \right.\\
[tex]\left \{ {{10 \geq x} \atop {4 < x }} \right.\\