1) x²-13x+42
D= 169-168=1
x1= (13+1)/2= 7
x2= (13-1)/2= 6
a= -6, b= -7
x²-13x+42= (x-6)*(x-7)
2) 2*((x+a)+(x+b)) - периметр
2*(x-6+x-7)= 2*(2x-13)= 4x-26
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Verified answer
1) x²-13x+42
D= 169-168=1
x1= (13+1)/2= 7
x2= (13-1)/2= 6
a= -6, b= -7
x²-13x+42= (x-6)*(x-7)
2) 2*((x+a)+(x+b)) - периметр
2*(x-6+x-7)= 2*(2x-13)= 4x-26