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alohomora604
@alohomora604
June 2022
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Алгебра 7 класс
Разложите на множители:
х³+27у³-(х+3у)*3ху=...
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novo51
Х³+27у³-(х+3у)*3ху=(х+3у)(х²-3ху+9у²)-(х+3у)*3ху=
=(х+3у)(х²-3ху+9у²-3ху)=(х+3у)(х²-6ху+9у²)=(х+3у)(х-3у)²=(х²-9у²)(х-3у)
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Answers & Comments
=(х+3у)(х²-3ху+9у²-3ху)=(х+3у)(х²-6ху+9у²)=(х+3у)(х-3у)²=(х²-9у²)(х-3у)