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kkristazz
@kkristazz
March 2022
2
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Алгебра, 9 класс. 100 баллов.
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Dedagenn
Task/28742596 Упростить выражение
-------------------
(2sin5α*cosα - sin4α )
/
sin12α = ( sin(5α+α) +sin(5α - α) - sin4α )
/
sin12α =
( sin6α +sin4α - sin4α )
/
sin(2*6α ) =sin6α
/
2sin6α*cos6α =
1 / 2cos6α .
* * * sin(α +β) = sinα*cosβ + cosα*sinβ , sin(α -β) =sinα*cosβ - cosα*sinβ ⇒
sin(α +β) + sin(α -β) =2sinα*cosβ * * *
1 votes
Thanks 2
kkristazz
что такое sec?
oganesbagoyan
Verified answer
(s6a+s4a-s4a)/s12a, s6a/s(2*6*a)=s6a/2*s6a*c6a= 1/(2*cos6a)=1/2*sec6a
1 votes
Thanks 1
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Answers & Comments
-------------------
(2sin5α*cosα - sin4α ) / sin12α = ( sin(5α+α) +sin(5α - α) - sin4α ) / sin12α =
( sin6α +sin4α - sin4α ) / sin(2*6α ) =sin6α / 2sin6α*cos6α = 1 / 2cos6α .
* * * sin(α +β) = sinα*cosβ + cosα*sinβ , sin(α -β) =sinα*cosβ - cosα*sinβ ⇒
sin(α +β) + sin(α -β) =2sinα*cosβ * * *
Verified answer
(s6a+s4a-s4a)/s12a, s6a/s(2*6*a)=s6a/2*s6a*c6a= 1/(2*cos6a)=1/2*sec6a