log(a) b = 1/log(b) a
log² (0.1) z = 9/log(z) 0.1 - 20
одз x > 0 z ≠ 1
log² (0.1) z = 9*log(0.1) z - 20
log(0.1) z = t
t² - 9t + 20 = 0
по теореме виета t = 4 и 5
1. t = 4
log(0.1) z = 4
z = (1/10)^4 = 1/10000
1. t = 5
log(0.1) z = 5
z = (1/10)^5 = 1/100000
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Verified answer
log(a) b = 1/log(b) a
log² (0.1) z = 9/log(z) 0.1 - 20
одз x > 0 z ≠ 1
log² (0.1) z = 9*log(0.1) z - 20
log(0.1) z = t
t² - 9t + 20 = 0
по теореме виета t = 4 и 5
1. t = 4
log(0.1) z = 4
z = (1/10)^4 = 1/10000
1. t = 5
log(0.1) z = 5
z = (1/10)^5 = 1/100000