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myrmyr13
@myrmyr13
July 2022
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Алгебра. Помогите пожалуйста 2-4
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DashaV19022001
4.
(а) ( х - 4 )² + ( х - 6 )² = 2
( х - 4 )( х + 4 ) + ( х - 6 )( х + 6 ) = 2
х² + 4х - 4х - 16 + х² + 6х - 6х - 36 = 2
2х² - 46 = 2
2х² = 48
х² = 24
х = √24
(б) (3х² - 2х)/4 - (2х²-2)/3 = 0
( 3(3х² - 2х) - 4(2х²-2) ) / 12 = 0
( 9х² - 6х - 8x² - 8 ) / 12 = 0
( х² - 6х - 8 ) / 12 = 0
х² - 6х - 8 = 0
a = 1, b = -6, c = -8
D = b² - 4ac = (-6)² - 4 * 1 * (-8) = 36 + 32 = 68
√D = √68
x1 = (-b - √D)/2а = ( 6 - √68)/2
x2 = (-b + √D)/2а = ( 6 + √68)/2
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Answers & Comments
(а) ( х - 4 )² + ( х - 6 )² = 2
( х - 4 )( х + 4 ) + ( х - 6 )( х + 6 ) = 2
х² + 4х - 4х - 16 + х² + 6х - 6х - 36 = 2
2х² - 46 = 2
2х² = 48
х² = 24
х = √24
(б) (3х² - 2х)/4 - (2х²-2)/3 = 0
( 3(3х² - 2х) - 4(2х²-2) ) / 12 = 0
( 9х² - 6х - 8x² - 8 ) / 12 = 0
( х² - 6х - 8 ) / 12 = 0
х² - 6х - 8 = 0
a = 1, b = -6, c = -8
D = b² - 4ac = (-6)² - 4 * 1 * (-8) = 36 + 32 = 68
√D = √68
x1 = (-b - √D)/2а = ( 6 - √68)/2
x2 = (-b + √D)/2а = ( 6 + √68)/2