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inkabtg
@inkabtg
September 2021
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Алгебра, помогите!!!!!!!!!!!!!
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ytekjdbvsq
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Пишите, если что не так
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sedinalana
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1)(x-y)/[(x-y)(x²+xy+y²)-(x+y)/[(x+y)(x²-xy+y²)]=1/(x²+xy+y²)+1/(x²-xy+y²)=
=(x²-xy+y²-x²-xy-y²)/[(x²+xy+y²)(x²-xy+y²)]=-2xy/[(x²+xy+y²)(x²-xy+y²)]
2)(x-y)+xy/(x-y)=(x²-2xy+y²+xy)/(x-y)=(x²-xy+y²)/(x-y)
3)(x+y)-xy/(x+y)=(x²+2xy+y²-xy)/(x+y)=(x²+xy+y²)/(x+y)
4)-2xy/[(x²+xy+y²)(x²-xy+y²)] *(x²-xy+y²)/(x-y)*(x²+xy+y²)/(x+y)=
=-2xy/(x²-y²)=2xy/(y²-x²)
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Answers & Comments
Verified answer
Пишите, если что не такVerified answer
1)(x-y)/[(x-y)(x²+xy+y²)-(x+y)/[(x+y)(x²-xy+y²)]=1/(x²+xy+y²)+1/(x²-xy+y²)==(x²-xy+y²-x²-xy-y²)/[(x²+xy+y²)(x²-xy+y²)]=-2xy/[(x²+xy+y²)(x²-xy+y²)]
2)(x-y)+xy/(x-y)=(x²-2xy+y²+xy)/(x-y)=(x²-xy+y²)/(x-y)
3)(x+y)-xy/(x+y)=(x²+2xy+y²-xy)/(x+y)=(x²+xy+y²)/(x+y)
4)-2xy/[(x²+xy+y²)(x²-xy+y²)] *(x²-xy+y²)/(x-y)*(x²+xy+y²)/(x+y)=
=-2xy/(x²-y²)=2xy/(y²-x²)