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otashkaakramov
@otashkaakramov
August 2021
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Алгебра проверь себя 9 класс стр 39 1 уровень
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oganesbagoyan
Verified answer
1.
а)
3^(-5) : 3^(-7) -2^(-2)*2^4 +((2/3)^(-1))^3 =3² -2² +(3/2)³
=67/ 8
.
б)
((3¹⁰)*(32)) (^1/5) -∛48/(∛2*∛3) = ((3¹⁰)*(2⁵)) (^1/5) -∛48/(∛(2*3) =
3²*2 - ∛(48/6) =18 -2
=16.
в)
25^(3/2)*25^(-1) + (5³)^(2/3): 5³ -48^(2/3):6^(2/3) =5³/25 +5²/5³ -(48/6)^(2/3) =
5 +1/5 - (2³)^(2/3) = 5 +1/5 -2²
= 1,2.
------------
2.
8600 =0,86*10⁴ ; 0,0076 =0,76*10^(-2) .
---
0,86*10⁴ *0,76*10^(-2) =0,86*0,76*10² =0,6536*10².
0,86*10⁴ : 0,76*10^(-2) = (0,86/ 0,76) *10⁶ ≈ 0,1132*10⁷ .
------------
3.
а)
3x ^(-9)*2x⁵/ x^(-4) =6x^(-4)/x^(-4) = 6 . * * * x≠0 * * *
б)
(x ^(-1) +y^(-1))*(1/xy)^(-2) =(1/x+1/y) * (xy)² = xy(x+y).
------------
4.
a ^(5/3) / (∛a²) *a^(1/4)) = a / a^(1/4) =a ^(3/4) , если a=81 то :
=81^(3/4) =(3⁴)^(3/4) =3³ =27.
------------
5.
0,76^(2/3) =∛0,76²
>
∛ 0,67² = 0,67^(2/3)
;
( 3,09)^(-1/3) =1/∛(3,09)
<
1/∛(3,08) =( 3,08)^(-1/3) .
10 votes
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Answers & Comments
Verified answer
1.а) 3^(-5) : 3^(-7) -2^(-2)*2^4 +((2/3)^(-1))^3 =3² -2² +(3/2)³ =67/ 8.
б) ((3¹⁰)*(32)) (^1/5) -∛48/(∛2*∛3) = ((3¹⁰)*(2⁵)) (^1/5) -∛48/(∛(2*3) =
3²*2 - ∛(48/6) =18 -2 =16.
в) 25^(3/2)*25^(-1) + (5³)^(2/3): 5³ -48^(2/3):6^(2/3) =5³/25 +5²/5³ -(48/6)^(2/3) =
5 +1/5 - (2³)^(2/3) = 5 +1/5 -2² = 1,2.
------------
2. 8600 =0,86*10⁴ ; 0,0076 =0,76*10^(-2) .
---
0,86*10⁴ *0,76*10^(-2) =0,86*0,76*10² =0,6536*10².
0,86*10⁴ : 0,76*10^(-2) = (0,86/ 0,76) *10⁶ ≈ 0,1132*10⁷ .
------------
3.
а) 3x ^(-9)*2x⁵/ x^(-4) =6x^(-4)/x^(-4) = 6 . * * * x≠0 * * *
б) (x ^(-1) +y^(-1))*(1/xy)^(-2) =(1/x+1/y) * (xy)² = xy(x+y).
------------
4. a ^(5/3) / (∛a²) *a^(1/4)) = a / a^(1/4) =a ^(3/4) , если a=81 то :
=81^(3/4) =(3⁴)^(3/4) =3³ =27.
------------
5. 0,76^(2/3) =∛0,76² >∛ 0,67² = 0,67^(2/3) ;
( 3,09)^(-1/3) =1/∛(3,09) < 1/∛(3,08) =( 3,08)^(-1/3) .