a) 9-(3+а)(2а+3) = 9-(6а+9+2а²+3а) = 9-9а-9-2а² = 9а-2а²
б) 4а³+(а-а²)(3+4а) = 4а³+3а+4а²-3а²-4а³ = 3а+а²
в) (1-2х)(2+х)+(1-х)(2-2х) = 2+x-4х-2х²+2-2х-2х+2х² = 4-7х
г) (х-3)(х-4)-(х-5)(х-2) = х²-4х-3х+12-(х²-2х-5х+10) = х²-4х-3х+12-х²+2х+5х-10 = 12-10 = 2
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Answers & Comments
a) 9-(3+а)(2а+3) = 9-(6а+9+2а²+3а) = 9-9а-9-2а² = 9а-2а²
б) 4а³+(а-а²)(3+4а) = 4а³+3а+4а²-3а²-4а³ = 3а+а²
в) (1-2х)(2+х)+(1-х)(2-2х) = 2+x-4х-2х²+2-2х-2х+2х² = 4-7х
г) (х-3)(х-4)-(х-5)(х-2) = х²-4х-3х+12-(х²-2х-5х+10) = х²-4х-3х+12-х²+2х+5х-10 = 12-10 = 2