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iragaenko03
@iragaenko03
July 2022
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Алгебра,11 класс.Помогите пожалуйста
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zinaidazina
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свойство показательной функции
1)
2)
3)
4)
2 votes
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Answers & Comments
1)![4^{log_29}=(2^2)^{log_29}=(2^{log_29})^2=9^2=81 4^{log_29}=(2^2)^{log_29}=(2^{log_29})^2=9^2=81](https://tex.z-dn.net/?f=4%5E%7Blog_29%7D%3D%282%5E2%29%5E%7Blog_29%7D%3D%282%5E%7Blog_29%7D%29%5E2%3D9%5E2%3D81)
2)![(\frac{1}{9} )^{-2log_312}=9^{2log_312}=(3^2)^{2log_312}=(3^{log_312^2})^2=(12^2)^2=12^4=20736 (\frac{1}{9} )^{-2log_312}=9^{2log_312}=(3^2)^{2log_312}=(3^{log_312^2})^2=(12^2)^2=12^4=20736](https://tex.z-dn.net/?f=%28%5Cfrac%7B1%7D%7B9%7D%20%29%5E%7B-2log_312%7D%3D9%5E%7B2log_312%7D%3D%283%5E2%29%5E%7B2log_312%7D%3D%283%5E%7Blog_312%5E2%7D%29%5E2%3D%2812%5E2%29%5E2%3D12%5E4%3D20736)
3)![10^{2+lg8}=10^{2}*10^{lg8}=100*8=800 10^{2+lg8}=10^{2}*10^{lg8}=100*8=800](https://tex.z-dn.net/?f=10%5E%7B2%2Blg8%7D%3D10%5E%7B2%7D%2A10%5E%7Blg8%7D%3D100%2A8%3D800)
4)