Ответ:

50c⁴–21c³+3c²–30c+4

Объяснение:

2х–ау+bz

2*(5c³+2)–3c*(7c²–c+10)+10c³*(5c–1)= 10c³+4–21c³+3c²–30c+50c⁴–10c³= 50c⁴–21c³+3c²–30c+4