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AntonKo66
@AntonKo66
August 2022
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Al(OH)2Cl+2KCl=AlCl3+2KOH расписать на ионы помогите
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IrVB
Al(OH)2Cl + 2KCl = AlCl3 + 2KOH
Al(OH)₂⁺ + Cl⁻ + 2K⁺ + 2Cl⁻ = Al³⁺ + 3Cl⁻ + 2K⁺ + 2OH⁻
Al(OH)₂⁺ = Al³⁺ + 2OH⁻
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Answers & Comments
Al(OH)₂⁺ + Cl⁻ + 2K⁺ + 2Cl⁻ = Al³⁺ + 3Cl⁻ + 2K⁺ + 2OH⁻
Al(OH)₂⁺ = Al³⁺ + 2OH⁻