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sibunes
@sibunes
July 2022
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AL(OH)3+NaOH=NaAL(OH)4 полное и сокращенное ионно-молекулярное уравнение
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IrVB
Verified answer
Al(OH)3 + NaOH = Na[Al(OH)4]
Al(OH)3 + Na⁺ + OH⁻ = Na⁺ + [Al(OH)4]⁻
Al(OH)3 + OH⁻ = [Al(OH)4]⁻
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Verified answer
Al(OH)3 + NaOH = Na[Al(OH)4]Al(OH)3 + Na⁺ + OH⁻ = Na⁺ + [Al(OH)4]⁻
Al(OH)3 + OH⁻ = [Al(OH)4]⁻