Арефметическая прогрессия задана условиями а1=-1;аn+1=an+3. Найти а11-?. Created by Katerina286. matematika-ru

Арефметическая прогрессия задана условиями а1=-1;аn+1=an+3. Найти а11-?...

August 2022 1 20 Report

Арефметическая прогрессия задана условиями а1=-1;аn+1=an+3. Найти а11-?

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558Egor558 A1 = 5an+1 = an - 3a10 — ? a2 = 5 – 3 = 2a3 = 2 – 3 = -1a4 = -1 – 3 = -4a5 = -4 – 3 = -7a6 = -7 – 3 = -10a7 = -10 – 3 = -13a8 = -13 – 3 = -16a9 = -16 – 3 = -19a10 = -19 – 3 = -22

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