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baxar2011
@baxar2011
July 2022
1
7
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арифметическая прогрессия
А3=9
А7=1
d=?
Sn=?
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Answers & Comments
Alexandr130398
A5=(A3+A7)/2=(9+1)/2=5
A4=(A3+A5)/2=(9+5)/2=7
d
=A4-A3=7-9=
-2
An=A1+d(n-1)
A3=A1+2d
A1=A3-2d=9-2*(-2)=9+4=13
An=A1+d(n-1)=13-2(n-1)=13-2n+2=15-2n
Sn
=(A1+An)n/2=(13+15-2n)n/2=(28-2n)n/2=(14-n)n=
14n-n²
3 votes
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Answers & Comments
A4=(A3+A5)/2=(9+5)/2=7
d=A4-A3=7-9=-2
An=A1+d(n-1)
A3=A1+2d
A1=A3-2d=9-2*(-2)=9+4=13
An=A1+d(n-1)=13-2(n-1)=13-2n+2=15-2n
Sn=(A1+An)n/2=(13+15-2n)n/2=(28-2n)n/2=(14-n)n=14n-n²