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DashaWayne
@DashaWayne
July 2022
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арифметическая прогрессия an задана условиями a1=4 an+1=an+3 найдите сумму первых 5 членов этой прогрессии с четными номерами
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Ayajan02
A1=4
an+1=a1+3
a5=?
a5=a1+4d
a5=4+4d
4d=4
d=1
a5=4+4=8
an+1=a1+d
an+1=a1+1
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Answers & Comments
an+1=a1+3
a5=?
a5=a1+4d
a5=4+4d
4d=4
d=1
a5=4+4=8
an+1=a1+d
an+1=a1+1