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Galagyzarus
@Galagyzarus
July 2022
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АВ=1см,АС=2см,угол А=30°,найти ВС
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Veteran2016
По теореме косинусов:
BC^2=AB^2+AC^2-2*AB*AC*CosA = 1^2+2^2-2*1*2*(√3/2)= 5-2√3
BC=
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Answers & Comments
BC^2=AB^2+AC^2-2*AB*AC*CosA = 1^2+2^2-2*1*2*(√3/2)= 5-2√3
BC=