Ответ:
Объяснение:
S1 = S/4
S2= 3*S / 4
S= S1+S2
V1 = 40 км/ч
V2= 60км/ч
Vc = ?
t1=S1/V1 = S/(4*V1)
t2=S2/V2 = 3*S/(4*V2)
Vc = S/(t1+t2) = S / (S/(4*V1) + (3*S/(4*V2))) = 1/ (1/(4*V1) + (3/(4*V2) =
1/(1/(4*40) + 3/(4*60)) = 1/(1/(160) + 3/(240)) = =53.3 км/ч
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Verified answer
Ответ:
Объяснение:
S1 = S/4
S2= 3*S / 4
S= S1+S2
V1 = 40 км/ч
V2= 60км/ч
Vc = ?
t1=S1/V1 = S/(4*V1)
t2=S2/V2 = 3*S/(4*V2)
Vc = S/(t1+t2) = S / (S/(4*V1) + (3*S/(4*V2))) = 1/ (1/(4*V1) + (3/(4*V2) =
1/(1/(4*40) + 3/(4*60)) = 1/(1/(160) + 3/(240)) = =53.3 км/ч