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HELPME986
@HELPME986
August 2022
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а) x(x+3)-4(x-5)=7(x+4)-8 решите уравнение ..пожалуйста поэтапно!
б) 2x^4-9x^2+4=0(а здесь через t)
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русская25
а) x(x+3)-4(x-5)=7(x+4)-8
x
²+3x-4x+20=7x+28-8
x²-8x=0
x(x-8)=0
x₁=0
х₂=8
Ответ: 0;8.
2x
⁴
-9x
²
+4=0
Замена: х²=t
2t²-9t+4=0
D= 81-32=49
t₁= 9+7/4= 4
t₂= 9-7/4= 1/2
х²= 4
х₁,₂= +-2
х₃,₄= +- 1/√2 = +- √2/2
Ответ: +- 2; +- √2/2.
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Answers & Comments
x²+3x-4x+20=7x+28-8
x²-8x=0
x(x-8)=0
x₁=0
х₂=8
Ответ: 0;8.
2x⁴-9x²+4=0
Замена: х²=t
2t²-9t+4=0
D= 81-32=49
t₁= 9+7/4= 4
t₂= 9-7/4= 1/2
х²= 4
х₁,₂= +-2
х₃,₄= +- 1/√2 = +- √2/2
Ответ: +- 2; +- √2/2.