P+q/pq к знаменателю p²q3/a+3 к знаменателю 2a+62/b-1 к знаменателю 4b-4. Created by gvsxx. algebra-ru

b-1 к знаменателю 4b-4...

NNNLLL54

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$\frac{p+q}{pq}=\frac{p(p+q)}{p^2q}\\\\\frac{3}{a+3}=\frac{2\cdot 3}{2(a+4)}=\frac{6}{2a+6}\\\\\frac{2}{b-1}=\frac{4\cdot 2}{4(b-1)}=\frac{8}{4b-4}$

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Vladislav006

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$\frac{p+q}{pq} = \frac{(p+q)*p}{pq*p} = \frac{p(p+q)}{p^2q}$

$\frac{3}{a+3} = \frac{3*2}{(a+3)*2} = \frac{6}{2a+6}$

$\frac{2}{b-1} = \frac{2*4}{(b-1)*4} = \frac{8}{4b-4}$

2 votes Thanks 2

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