(b²-3)³-(b²-3)*(b⁴+3b²+9)...

aitmuhammed @aitmuhammed

October 2021 1 0 Report

(b²-3)³-(b²-3)*(b⁴+3b²+9)

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Эксперт5

Verified answer

(b²-3)³-(b²-3)(b⁴+3b²+9)=
=(b²-3)((b²-3)²-(b⁴+3b²+9))=
=(b²-3)(b⁴-6b²+9-b⁴-3b²-9)=
=(b²-3)(-9b²)=
= -9b⁴+27b²

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