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Karamellka18
@Karamellka18
July 2022
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(b-4)·(b+4)-(b-3)·(b+5)=
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belyc
B^2-16-(b^2-3b+5b-15)=b^2-16-b^2+3b-5b-15=-2b-31
Вроде так.
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Эдвайна
(b-4)•(b+4)-(b-3)•(b+5)=b^2+4b-4b-16-(b^2+5b-3b-15)=b^2-16-b^2-5b+3b+15=-16-5b+3b=-16-2b
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Thanks 0
Эдвайна
Я перепутала
b^2-16-b^2-5b+3b+15=-16-5b+3b+15=-2b-1
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Answers & Comments
Вроде так.
b^2-16-b^2-5b+3b+15=-16-5b+3b+15=-2b-1