b(1)+b(2)+b(3)=35 b(1)^2+b(2)^2+b(3)^2=525 геометрическая прогресия b(1)-? q-?. Created by alisher270502. matematika-ru

b(1)+b(2)+b(3)=35 b(1)^2+b(2)^2+b(3)^2=525 геометрическая прогресия b(1)-? q-?...

alisher270502 @alisher270502

August 2022 1 15 Report

b(1)+b(2)+b(3)=35
b(1)^2+b(2)^2+b(3)^2=525 геометрическая прогресия
b(1)-? q-?

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IrkaShevko

Verified answer

B2 = b1*q

b3 = b1 * q²

b1(1 + q + q²) = 35
b1²(1 + q² + q⁴) = 525

возведем первое в квадрат

b1²(1 + q² + q⁴ + 2q + 2q² + 2q³) = 1225
b1²(1 + q² + q⁴) = 525

b1²(1 + q² + q⁴) + 2q*b1²(1 + q + q²) = 1225
525 + 2q*b1*35 = 1225

70q*b1 = 700
q*b1 = 10

b1 = 10/q

10(1 + q + q²)/q = 35

2 + 2q + 2q² = 7q

2q² - 5q + 2 = 0

D = 25 - 16 = 9
q = 1/2 или q = 2

b1 = 20 или b1 = 5

Ответ: b1 = 20, q = 0,5 или b1 = 5, q = 2

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Answers & Comments

Verified answer

skolko gramm oksida fosfora5 obrazuetsya kogda 8 mol fosfora sgoreli v kislor

vsem izvestno chto metally v rasplavlennom vide imeyut raznye plotnostikak polucha

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