Ответ:
первое.
(2х²-3у)² = (2х²)² - 2·2х²·3у + (3у)² = 4х²-12х²у+9у²
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Ответ:
первое.
(2х²-3у)² = (2х²)² - 2·2х²·3у + (3у)² = 4х²-12х²у+9у²