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anzoamore
@anzoamore
July 2022
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решите систему уравнений а+b=9 / b^2+a=29
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vanyaavdeev1
а+b=9
b²+a=29
из первого а=9-в
в²+9-в=9
в²-в=0
в(в-1)=0
в₁=0 в₂=1
а₁=9-0=9 а₂=9-1=8
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miron2077
Verified answer
B^2+9-b=29
b^2-b-20=0
D=1+4*20=81=9^2
b1=(1+9)/2=5
b2=(1-9)/2=-4
a1=9-5 a1=4
a2=9+4 a2=13
0 votes
Thanks 0
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Answers & Comments
b²+a=29
из первого а=9-в
в²+9-в=9
в²-в=0
в(в-1)=0
в₁=0 в₂=1
а₁=9-0=9 а₂=9-1=8
Verified answer
B^2+9-b=29b^2-b-20=0
D=1+4*20=81=9^2
b1=(1+9)/2=5
b2=(1-9)/2=-4
a1=9-5 a1=4
a2=9+4 a2=13