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doc11238
@doc11238
August 2022
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b^4-1=(b-1)(b^3+b^2+b+1)
а^4-1=(а-1)(а^3+а^2+а+1)
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Answers & Comments
Vendy219
1) b⁴-1 = (b-1)(b³+b²+b+1)
b⁴-1 = b⁴+b³+b²+b-b³-b²-b-1
b⁴-1 = b⁴-1
2) a⁴-1 = (a-1)(a³+a²+a+1)
a⁴-1 = a⁴+a³+a²+a-a³-a²-a-1
a⁴-1 = a⁴-1
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Answers & Comments
b⁴-1 = b⁴+b³+b²+b-b³-b²-b-1
b⁴-1 = b⁴-1
2) a⁴-1 = (a-1)(a³+a²+a+1)
a⁴-1 = a⁴+a³+a²+a-a³-a²-a-1
a⁴-1 = a⁴-1