Ответ:
[tex]x = 1[/tex]
решение на фото
[tex]3-\frac{2}{3-\frac{2}{3-\frac{2}{x} } } =1\\3-\frac{2}{\frac{3x-2}{x} } =1\\3-\frac{2}{\frac{9x-6-2x}{3x-2} }=1 \\3-\frac{2}{\frac{7x-6}{3x-2} } =1\\3-\frac{2(3x-2)}{7x-6}=1\\ 3-\frac{6x-4}{7x-6}=1\\ \frac{3(7x-6)-(6x-4)}{7x-6}=1\\ \frac{21x-18-6x+4}{7x-6}=1\\ \frac{15x-14}{7x-6}=1\\ 7x-6=15x-14\\-8x=-8\\x=1\\[/tex]
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Ответ:
[tex]x = 1[/tex]
решение на фото
Verified answer
[tex]3-\frac{2}{3-\frac{2}{3-\frac{2}{x} } } =1\\3-\frac{2}{\frac{3x-2}{x} } =1\\3-\frac{2}{\frac{9x-6-2x}{3x-2} }=1 \\3-\frac{2}{\frac{7x-6}{3x-2} } =1\\3-\frac{2(3x-2)}{7x-6}=1\\ 3-\frac{6x-4}{7x-6}=1\\ \frac{3(7x-6)-(6x-4)}{7x-6}=1\\ \frac{21x-18-6x+4}{7x-6}=1\\ \frac{15x-14}{7x-6}=1\\ 7x-6=15x-14\\-8x=-8\\x=1\\[/tex]