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dadyaZhenya
@dadyaZhenya
August 2021
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Ba(OH)2 Масова частка елемента
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krioira
Mr(Ba(OH)2) = 137+2*16+2*1= 171
W(Ba)= 137/171 = 0.80=80%
W(O)=32/171=0.19=19%
W(H)=2/171=0.01=1%
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Answers & Comments
W(Ba)= 137/171 = 0.80=80%
W(O)=32/171=0.19=19%
W(H)=2/171=0.01=1%