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КириллУмник11
@КириллУмник11
July 2022
2
4
Report
Ba(OH)2+FeBr2=
MnCl2+AgNo3=
NaOH+H3Po4=
решить
разложить на ионную
формулу и на неполную ионную формулы
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Answers & Comments
svetka1574
Verified answer
3Ba(OH)2 +2 FeBr3 -> 2Fe(OH)3 + 3BaBr2
3Ba(+2) + 6OH(-) + 2Fe(+3) + 6Br(-) -> 2Fe(OH)3 + 3Ba(+2) + 6Br(-)
2Fe(+3) + 6OH(-) -> 2Fe(OH)3
MnCl2 + 2AgNO3 -> Mn(NO3)2 + 2AgCl
Mn(+2) + 2Cl(-) + 2Ag(+) + 2NO3(-) -> Mn(+2) + 2NO3(-) + 2AgCl
2Ag(+) + 2Cl(-) -> 2AgCl
3NaOH + H3PO4 -> Na3PO4 + 3H2O
3Na(+) + 3OH(-) + 3H(+) + PO4(-3) -> 3Na(+) + PO4(-3) + 3H2O
3OH(-)+3H(+) -> 3H2O
0 votes
Thanks 1
Alexei78
Verified answer
Ba(OH)2+FeBr2-->Fe(OH)2+BaBr2
Ba²⁺+2OH⁻+Fe²⁺+2Br⁻-->Fe(OH)2+Ba²⁺+2Br⁻
2OH⁻+Fe²⁺-->Fe(OH)2
MnCL2+2AgNO3-->Mn(NO3)2+2AgCL
Mn²⁺+2CL⁻+2Ag⁺+2NO⁻₃-->Mn²⁺+2NO⁻₃+2AgCL
2CL⁻+2Ag⁺-->2AgCL
3NaOH+H3PO4-->Na3PO4+3H2O
3Na⁺+3OH⁻+3H⁺+PO³⁻₄-->3Na⁺+PO⁻₄+3H2O
3OH⁻+3H⁺-->3H2O
0 votes
Thanks 2
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Answers & Comments
Verified answer
3Ba(OH)2 +2 FeBr3 -> 2Fe(OH)3 + 3BaBr23Ba(+2) + 6OH(-) + 2Fe(+3) + 6Br(-) -> 2Fe(OH)3 + 3Ba(+2) + 6Br(-)
2Fe(+3) + 6OH(-) -> 2Fe(OH)3
MnCl2 + 2AgNO3 -> Mn(NO3)2 + 2AgCl
Mn(+2) + 2Cl(-) + 2Ag(+) + 2NO3(-) -> Mn(+2) + 2NO3(-) + 2AgCl
2Ag(+) + 2Cl(-) -> 2AgCl
3NaOH + H3PO4 -> Na3PO4 + 3H2O
3Na(+) + 3OH(-) + 3H(+) + PO4(-3) -> 3Na(+) + PO4(-3) + 3H2O
3OH(-)+3H(+) -> 3H2O
Verified answer
Ba(OH)2+FeBr2-->Fe(OH)2+BaBr2Ba²⁺+2OH⁻+Fe²⁺+2Br⁻-->Fe(OH)2+Ba²⁺+2Br⁻
2OH⁻+Fe²⁺-->Fe(OH)2
MnCL2+2AgNO3-->Mn(NO3)2+2AgCL
Mn²⁺+2CL⁻+2Ag⁺+2NO⁻₃-->Mn²⁺+2NO⁻₃+2AgCL
2CL⁻+2Ag⁺-->2AgCL
3NaOH+H3PO4-->Na3PO4+3H2O
3Na⁺+3OH⁻+3H⁺+PO³⁻₄-->3Na⁺+PO⁻₄+3H2O
3OH⁻+3H⁺-->3H2O