[tex]\displaystyle \frac{6x^2+7x-5}{1-2x}=4,x\neq \frac{1}{2}\\ \\\frac{6x^2+10x-3x-5}{-(2x-1)}=4\\ \\\frac{2x(3x+5)-(3x+5)}{-(2x-1)}=4\\ \\\frac{(3x+5)(2x-1)}{-(2x-1)}=4\\ \\(3x+5)(-1)=4\\-3x-5=4\\-3x=4+5\\-3x=9\\x=-3[/tex]
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[tex]\displaystyle \frac{6x^2+7x-5}{1-2x}=4,x\neq \frac{1}{2}\\ \\\frac{6x^2+10x-3x-5}{-(2x-1)}=4\\ \\\frac{2x(3x+5)-(3x+5)}{-(2x-1)}=4\\ \\\frac{(3x+5)(2x-1)}{-(2x-1)}=4\\ \\(3x+5)(-1)=4\\-3x-5=4\\-3x=4+5\\-3x=9\\x=-3[/tex]