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ASnezuki123
@ASnezuki123
August 2022
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Помогите пожалуйста, не успеваю...
(1/а+1/b+c)/(1/a-1/b+c) при а=2,1 b=1,8 с=1,3
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sedinalana
Verified answer
1/a+1/(b+c)=(b+c+a)/a(b+c)
1/a-1/(b+c)=(b+c-a)/a(b+b)
(a+b+c)/a(b+c)*a(b+c)/(b+c-a)=(a+b+c)/(b+c-a)=(2,1+1,8+1,3)/(1,8+1,3-2,1)=
=5,2/1=5,2
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Answers & Comments
Verified answer
1/a+1/(b+c)=(b+c+a)/a(b+c)1/a-1/(b+c)=(b+c-a)/a(b+b)
(a+b+c)/a(b+c)*a(b+c)/(b+c-a)=(a+b+c)/(b+c-a)=(2,1+1,8+1,3)/(1,8+1,3-2,1)=
=5,2/1=5,2