[tex]\displaystyle \frac{x^2+x}{x^2-25}=\frac{45-3x}{x^2-25},x\neq -5,x\neq 5\\ \\x^2+x=45-3x\\ x^2+x-45+3x=0\\x^2+4x-45=0\\x^2+9x-5x-45=0\\x(x+9)-5(x+9)=0\\(x+9)(x-5)=0\\x+9=0,x-5=0\\x=-9,x=5 \rightarrow x\neq 5\\x=-9[/tex]
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[tex]\displaystyle \frac{x^2+x}{x^2-25}=\frac{45-3x}{x^2-25},x\neq -5,x\neq 5\\ \\x^2+x=45-3x\\ x^2+x-45+3x=0\\x^2+4x-45=0\\x^2+9x-5x-45=0\\x(x+9)-5(x+9)=0\\(x+9)(x-5)=0\\x+9=0,x-5=0\\x=-9,x=5 \rightarrow x\neq 5\\x=-9[/tex]