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vvseZnaJka
@vvseZnaJka
July 2022
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Как представить в y: 5b/(b^2+1) если y=(2b^2+2)/b
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Universalka
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Y=(2b^2+2)/b, отсюда 2(b^2+1)=y*b или b^2+1=y*b/2. Тогда 5b/(b^2+1)=5b/(y*b/2)=10b/y*b=10/y.
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Y=(2b^2+2)/b, отсюда 2(b^2+1)=y*b или b^2+1=y*b/2. Тогда 5b/(b^2+1)=5b/(y*b/2)=10b/y*b=10/y.