Ответ:
x=±π/8+πn/2+π/24; n∈Z
Пошаговое объяснение:
f'(x)=cos(4x-π/6))*(4x-π/6)'=4*cos(4x-π/6)
по формуле (sin(kx+b))'=k*cos(kx+b)
4*cos(4x-π/6)=0
cos(4x-π/6)=0
(4x-π/6)=±arccos0+2πn; n∈Z
4x=±π/2+2πn+π/6; n∈Z
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Ответ:
x=±π/8+πn/2+π/24; n∈Z
Пошаговое объяснение:
f'(x)=cos(4x-π/6))*(4x-π/6)'=4*cos(4x-π/6)
по формуле (sin(kx+b))'=k*cos(kx+b)
4*cos(4x-π/6)=0
cos(4x-π/6)=0
(4x-π/6)=±arccos0+2πn; n∈Z
4x=±π/2+2πn+π/6; n∈Z
x=±π/8+πn/2+π/24; n∈Z