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Куколка2014
@Куколка2014
August 2021
2
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Бегом !!
Решите этот приперчик)
Заранее спс
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sedinalana
Verified answer
Log(2)(x-1)³=6log(2)3
ОДЗ
x-1>0⇒x>1⇒x∈(1;∞)
log(2)(x-1)³=log(2)3^6
(x-1)³=3^6
x-1=9
x=9+1
x=10
0 votes
Thanks 1
Dимасuk
Verified answer
ОДЗ:
x - 1 > 0
x > 1
Воспользуемся свойством логарифма:
3log₂(x - 1) = 6log₂3
log₂(x - 1) = 2log₂3
log₂(x - 1) = log₂9
x - 1 = 9
x = 10
Ответ: x = 10.
0 votes
Thanks 1
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Answers & Comments
Verified answer
Log(2)(x-1)³=6log(2)3ОДЗ
x-1>0⇒x>1⇒x∈(1;∞)
log(2)(x-1)³=log(2)3^6
(x-1)³=3^6
x-1=9
x=9+1
x=10
Verified answer
ОДЗ:x - 1 > 0
x > 1
Воспользуемся свойством логарифма:
3log₂(x - 1) = 6log₂3
log₂(x - 1) = 2log₂3
log₂(x - 1) = log₂9
x - 1 = 9
x = 10
Ответ: x = 10.