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fortniteorpubg0287
@fortniteorpubg0287
July 2023
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Обчисліть масові частки елементів у сполуці Be(OH) 2
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1Manka1
Mr(Be(OH)2) = 9 + 16*2 + 1*2 = 43
W(Be) = Ar(Be) *n / Mr(Be(OH)2) *100% = 9 *1 / 43 *100% = 21%
W(O) =Ar(O) *n / Mr(Be(OH)2) *100% = 16*2 / 43 *100% = 74%
W(H) = Ar(H) *n / Mr(Be(OH)2) *100% = 1*2 / 43 *100% = 5%
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Answers & Comments
W(Be) = Ar(Be) *n / Mr(Be(OH)2) *100% = 9 *1 / 43 *100% = 21%
W(O) =Ar(O) *n / Mr(Be(OH)2) *100% = 16*2 / 43 *100% = 74%
W(H) = Ar(H) *n / Mr(Be(OH)2) *100% = 1*2 / 43 *100% = 5%