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vilentarasenko11
@vilentarasenko11
May 2022
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Будь ласка допоможіть з ціею роботою
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pushpull
Ответ:Пошаговое объяснение:3)[tex]\displaystyle \frac{3x}{7} = \frac{\pi }{2} +\pi n; n \in Z; \quad \Rightarrow x=\frac{7\pi }{6} +\frac{7\pi }{3} n; n \in Z[/tex]4)[tex]\displaystyle 3x-\frac{\pi }{8} =2\pi n; n \in Z; \quad \Rightarrow x= \frac{\pi }{24} +\frac{2\pi }{3} n; n \in Z[/tex]7) [tex]\displaystyle 6x+\frac{\pi }{3} =arccos(\frac{\pi }{3}) +2\pi n;n \in Z \quad \Rightarrow x = -\frac{\pi }{18} +\frac{1}{6} arccos(\frac{\pi }{3})+\frac{\pi }{3} n; n\in Z[/tex]8)[tex]\displaystyle -2x+\frac{\pi }{4} =\frac{\pi }{4} +2\pi n_1;n_1 \in Z \quad \Rightarrow x=-\frac{\pi }{4}n_1 ; n_1 \in Z[/tex][tex]\displaystyle -2x+\frac{\pi }{4} =\frac{3\pi }{2} +2\pi n_2;n_2 \in Z \quad \Rightarrow x=-\frac{3\pi }{16}-\frac{\pi }{4} n_2 ; n_2 \in Z[/tex]
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vilentarasenko11
Спасибо большое!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
pushpull
да не за что.... -))))
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