Ответ:
[tex]\frac{c+7b-c^{2} } {c}[/tex]
Если с=4, b=71, то [tex]\frac{4+7*71-(4^{2}) }{4} =\frac{4+497-16}{4} =\frac{485}{4} =121\frac{1}{4} =121,25[/tex]
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Answers & Comments
Ответ:
[tex]\frac{c+7b-c^{2} } {c}[/tex]
Если с=4, b=71, то [tex]\frac{4+7*71-(4^{2}) }{4} =\frac{4+497-16}{4} =\frac{485}{4} =121\frac{1}{4} =121,25[/tex]