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Asel1710
@Asel1710
September 2021
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(28c/c^2-49 + c-7/c+7):c+7/c +5-c/c-7
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sedinalana
Verified answer
1)28c/([(c-7)(c+7)]+(c-7)/(c+7)=(28c+c²-14c+49)/[(c-7)(c+7)]=
=(c²+14c+49)/[(c-7)(c+7)]=(c+7)²/[(c-7)(c+7)]=(c+7)/(c-7)
2)(c+7)/(c-7):(c+7)/c=(c+7)/(c-7)*c/(c+7)=c/(c-7)
3)c/(c-7)+(5-c)/(c-7)=(c+5-c)/(c-7)=5/(c-7)
23 votes
Thanks 62
obroten007
а ответ можете сказать
obroten007
здесь у вас просто три ответа
Asel1710
спасибо)
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Verified answer
1)28c/([(c-7)(c+7)]+(c-7)/(c+7)=(28c+c²-14c+49)/[(c-7)(c+7)]==(c²+14c+49)/[(c-7)(c+7)]=(c+7)²/[(c-7)(c+7)]=(c+7)/(c-7)
2)(c+7)/(c-7):(c+7)/c=(c+7)/(c-7)*c/(c+7)=c/(c-7)
3)c/(c-7)+(5-c)/(c-7)=(c+5-c)/(c-7)=5/(c-7)