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tanyavorobeva22
@tanyavorobeva22
October 2021
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Определите силу сопротивления движению, если вагонетка массой 1,2т под действием силы тяги 600Н приобрела ускорение 0,2м/c в квадрате
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coolbutcute
F=Fс-Fт, отсюда
Fc=Fт-F=Fт-ma=600-(1200*0,2)=600-240=360 Н
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Fc=Fт-F=Fт-ma=600-(1200*0,2)=600-240=360 Н