Объяснение:
[tex]x^2+12x-33=3\\x^2+12x-36=0\\D=12^2-4*1*(-36)=144+144=288.\\\sqrt{D}=\sqrt{288} =\sqrt{144*2} =12\sqrt{2}.\\ x_1=\frac{-12-12\sqrt{2} }{2}=-6-6\sqrt{2}.\\ x_2=\frac{-12+12\sqrt{2} }{2}=-6+6\sqrt{2}.[/tex]
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Объяснение:
[tex]x^2+12x-33=3\\x^2+12x-36=0\\D=12^2-4*1*(-36)=144+144=288.\\\sqrt{D}=\sqrt{288} =\sqrt{144*2} =12\sqrt{2}.\\ x_1=\frac{-12-12\sqrt{2} }{2}=-6-6\sqrt{2}.\\ x_2=\frac{-12+12\sqrt{2} }{2}=-6+6\sqrt{2}.[/tex]