Ответ:

Объяснение:

1)

[tex]\sqrt{49x} - \sqrt{25x}+\sqrt{4x}=\sqrt{49} * \sqrt{x}-\sqrt{25} * \sqrt{x}+\sqrt{4}*\sqrt{x}=7\sqrt{x}-5\sqrt{x}+2\sqrt{x}=4\sqrt{x}[/tex]

2)
[tex](\sqrt{3}-2)^2+4\sqrt{3}=9-4\sqrt{3}+4+4\sqrt{3}=13[/tex]

3)

[tex]\frac{\sqrt{14}-\sqrt{7}}{\sqrt{7}}=\frac{\sqrt{2}*\sqrt{7}-\sqrt{7}}{\sqrt{7}} =\sqrt{2}-1[/tex]

4)
[tex]\frac{\sqrt{3}-1}{\sqrt{3}+1}-\frac{\sqrt{3}+1}{\sqrt{3}-1} =\frac{(\sqrt{3}-1)^2-(\sqrt{3}+1)^2}{(\sqrt{3}+1)(\sqrt{3}-1)} = \frac{(\sqrt{3}-1-\sqrt{3}-1)(\sqrt{3}-1+\sqrt{3}+1)}{3-1} =\frac{-4\sqrt{3}}{2}=-2\sqrt{3}[/tex]

5)
[tex]\sqrt{36+10\sqrt{11}}=\sqrt{5^2+2*5*\sqrt{11}+\sqrt{11}^2}=\sqrt{(5+\sqrt{11})^2}=5+\sqrt{11}[/tex]