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cfyxjec1
@cfyxjec1
July 2022
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Тело массой 2 кг бросили с начальной скоростью 5 м/с с высоты 10 м. Чему будет равна кинетическая энергия тела в момент удара о землю? (Ускорение свободного падения g = 10 м/c2).
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flsh
E = mv^2/2 + mgh = m•(v^2/2 + gh) = 2•(5^2/2 + 10•10) = 225 Дж
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