[tex]\displaystyle (4a+\frac{1}{2}b-2)^2-2(-b+2ab-8a)=16a^2+\frac{1}{4}b^2+4+4ab-16a-2b+2b-4ab+16a=16a^2+\frac{1}{4}b^2+4[/tex]
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[tex]\displaystyle (4a+\frac{1}{2}b-2)^2-2(-b+2ab-8a)=16a^2+\frac{1}{4}b^2+4+4ab-16a-2b+2b-4ab+16a=16a^2+\frac{1}{4}b^2+4[/tex]